262 lines
6.5 KiB
JavaScript
262 lines
6.5 KiB
JavaScript
// bad stuff
|
|
|
|
function find_chords(chords, n) {
|
|
return chords.filter((c) => c[0].id === n.id || c[1].id === n.id);
|
|
}
|
|
|
|
function find_neighbours(chords, n) {
|
|
const c = find_chords(chords, n);
|
|
return c.map((c) => c[0].id === n.id ? c[1] : c[0])
|
|
}
|
|
|
|
|
|
|
|
// for a list of pairs [n1, n2] (these are nodes which share a common angle
|
|
// from a center), find all the groups of nodes which don't appear in a pair
|
|
// together
|
|
|
|
function partition_nodes(pairs) {
|
|
let groups = [];
|
|
const seen = new Set();
|
|
for( const pair of pairs ) {
|
|
// both nodes are in a group already
|
|
if( seen.has(pair[0]) && seen.has(pair[1]) ) {
|
|
continue;
|
|
}
|
|
let already = false;
|
|
// check if either node is already in a group
|
|
for( const group of groups ) {
|
|
if( group.has(pair[0]) ) {
|
|
group.add(pair[1]);
|
|
seen.add(pair[1]);
|
|
already = true;
|
|
continue;
|
|
} else if( group.has(pair[1]) ) {
|
|
group.has(pair[0]);
|
|
seen.has(pair[0]);
|
|
already = true;
|
|
continue;
|
|
}
|
|
}
|
|
// if neither of the pair was in a former group, start a new group
|
|
if( !already ) {
|
|
groups.push(new Set(pair));
|
|
}
|
|
// collapse any groups which now have common elements
|
|
groups = collapse_groups(groups);
|
|
}
|
|
return groups;
|
|
}
|
|
|
|
// given a list of groups, if any have common elements, collapse them
|
|
|
|
function collapse_groups(groups) {
|
|
const new_groups = [ ];
|
|
for( group of groups ) {
|
|
let collapsed = false;
|
|
for( new_group of new_groups ) {
|
|
const i = intersection(group, new_group);
|
|
if( i.size > 0 ) {
|
|
for( const e of group ) {
|
|
new_group.add(e);
|
|
}
|
|
collapsed = true;
|
|
break;
|
|
}
|
|
}
|
|
if( !collapsed ) {
|
|
new_groups.push(new Set(group));
|
|
}
|
|
}
|
|
return new_groups;
|
|
}
|
|
|
|
|
|
function intersection(s1, s2) {
|
|
const i = new Set();
|
|
for( const e of s1 ) {
|
|
if( s2.has(e) ) {
|
|
i.add(e)
|
|
}
|
|
}
|
|
return i;
|
|
}
|
|
|
|
function union(s1, s2) {
|
|
const u = new Set(s1);
|
|
for( const e of s2 ) {
|
|
u.add(e);
|
|
}
|
|
return u;
|
|
}
|
|
|
|
|
|
function vector_angle(n1, n2, n3) {
|
|
const v1 = new THREE.Vector4(n1.x, n1.y, n1.z, n1.w);
|
|
const v2 = new THREE.Vector4(n2.x, n2.y, n2.z, n2.w);
|
|
const v3 = new THREE.Vector4(n3.x, n3.y, n3.z, n3.w);
|
|
v2.sub(v1);
|
|
v3.sub(v1);
|
|
const dp = v2.dot(v3);
|
|
return Math.acos(dp / ( v2.length() * v3.length()));
|
|
}
|
|
|
|
function neighbour_angles_orig(chords, n) {
|
|
const ns = find_neighbours(chords, n);
|
|
const angles = {};
|
|
for( let i = 0; i < ns.length - 1; i++ ) {
|
|
for( let j = i + 1; j < ns.length; j++ ) {
|
|
const n2 = ns[i];
|
|
const n3 = ns[j];
|
|
const a = THREE.MathUtils.radToDeg(vector_angle(n, n2, n3));
|
|
const af = (a).toFixed(3);
|
|
if( ! (af in angles) ) {
|
|
angles[af] = [];
|
|
}
|
|
angles[af].push([n2.id, n3.id]);
|
|
}
|
|
}
|
|
return angles;
|
|
}
|
|
|
|
function neighbour_angles(chords, n, angle) {
|
|
const ns = find_neighbours(chords, n);
|
|
const pairs = [];
|
|
for( let i = 0; i < ns.length - 1; i++ ) {
|
|
for( let j = i + 1; j < ns.length; j++ ) {
|
|
const n2 = ns[i];
|
|
const n3 = ns[j];
|
|
const a = THREE.MathUtils.radToDeg(vector_angle(n, n2, n3));
|
|
const af = (a).toFixed(3);
|
|
if( af === angle ) {
|
|
pairs.push([n2.id, n3.id]);
|
|
}
|
|
}
|
|
}
|
|
return pairs;
|
|
}
|
|
|
|
|
|
function make_120_partition(nodes, n) {
|
|
const chords = find_all_chords(nodes);
|
|
const chord3 = chords["1.74806"]; // these are edges of the 600-cells;
|
|
const pairs60 = neighbour_angles(chord3, n, "60.000");
|
|
const icosas = partition_nodes(pairs60);
|
|
|
|
n.label = 1;
|
|
const angles = icosa_nodes(nodes, icosas[0]);
|
|
label_120_partition_r(nodes, chord3, 1, n, angles);
|
|
}
|
|
|
|
// recursive function to label a single 600-cell vertex partition of the
|
|
// 120-cell by following icosahedral nets
|
|
// this doesn't work! completely - labels only 108-112
|
|
|
|
function label_120_partition_r(nodes, chords, label, origin, neighbours) {
|
|
console.log(`label_120_partition_r ${origin.id}`);
|
|
console.log(neighbours.map((n) => n.id).join(', '));
|
|
|
|
// first try to label everything
|
|
const unlabelled = [];
|
|
for( const n of neighbours ) {
|
|
if( n.label === 0 ) {
|
|
console.log(`Labelled ${n.id} ${label}`);
|
|
n.label = label;
|
|
unlabelled.push(n);
|
|
} else if( n.label !== label ) {
|
|
console.log(`node ${n.id} is already in group ${n.label}`);
|
|
//return false;
|
|
}
|
|
}
|
|
for( const n of unlabelled ) {
|
|
// the angles represent two icosahedral pyramids - partition them and
|
|
// pick the one which is at 60 to the edge we arrived on
|
|
//console.log(`looking for more neighbors for ${n}`);
|
|
const pairs60 = neighbour_angles(chords, n, "60.000");
|
|
const icosas = partition_nodes(pairs60);
|
|
const icosa = choose_icosa(nodes, origin, n, icosas);
|
|
const icosa_n = icosa_nodes(nodes, icosa);
|
|
console.log(`recursing to ${nice_icosa(nodes,icosa)}`);
|
|
return label_120_partition_r(nodes, chords, label, n, icosa_n);
|
|
}
|
|
}
|
|
|
|
// given a pair of icosa-sets, pick the one which is at the right angle to
|
|
// the incoming vector
|
|
|
|
function choose_icosa(nodes, origin, n1, icosas) {
|
|
for( const icosa of icosas ) {
|
|
const inodes = icosa_nodes(nodes, icosa);
|
|
const a60 = inodes.map((ni) => {
|
|
const a = THREE.MathUtils.radToDeg(vector_angle(n1, origin, ni));
|
|
return a.toFixed(3);
|
|
});
|
|
if( a60.filter((a) => a === "60.000").length > 0 ) {
|
|
return icosa;
|
|
}
|
|
}
|
|
console.log("No icosa found!");
|
|
return undefined;
|
|
}
|
|
|
|
function icosa_nodes(nodes, icosa) {
|
|
return Array.from(icosa).map((nid) => node_by_id(nodes, nid)).sort((a, b) => a.id - b.id);
|
|
}
|
|
|
|
function node_by_id(nodes, nid) {
|
|
const ns = nodes.filter((n) => n.id === nid);
|
|
return ns[0];
|
|
}
|
|
|
|
|
|
function enumerate_icosas(nodes) {
|
|
const chords = find_all_chords(nodes);
|
|
const chord3 = chords["1.74806"]; // these are edges of the 600-cells;
|
|
|
|
for( const n of nodes ) {
|
|
const pairs60 = neighbour_angles(chord3, n, "60.000");
|
|
const icosas = partition_nodes(pairs60);
|
|
for( const icosa of icosas ) {
|
|
const inodes = icosa_nodes(nodes, icosa);
|
|
console.log(icosa_to_csv(n.id, inodes).join(','));
|
|
}
|
|
}
|
|
}
|
|
|
|
|
|
function icosa_to_csv(nid, icosa) {
|
|
const cols = [ nid ];
|
|
const ia = icosa.map((n) => n.id);
|
|
for( let i = 1; i < 601; i++ ) {
|
|
if( ia.includes(i) ) {
|
|
cols.push(i);
|
|
} else {
|
|
cols.push('')
|
|
}
|
|
}
|
|
return cols;
|
|
}
|
|
|
|
|
|
function start_icosas(nodes, chords, origin) {
|
|
const pairs60 = neighbour_angles(chords, origin, "60.000");
|
|
return partition_nodes(pairs60).map((i) => nice_icosa(nodes, i));
|
|
}
|
|
|
|
|
|
|
|
function next_icosa(nodes, chords, origin, nid) {
|
|
const n = node_by_id(nodes, nid);
|
|
const pairs60 = neighbour_angles(chords, n, "60.000");
|
|
const icosas = partition_nodes(pairs60);
|
|
const icosa = choose_icosa(nodes, origin, n, icosas);
|
|
|
|
return nice_icosa(nodes, icosa);
|
|
}
|
|
|
|
function nice_icosa(nodes, icosa) {
|
|
return icosa_nodes(nodes, icosa).map((n) => n.id).join(', ');
|
|
}
|
|
|
|
|