49 lines
1.2 KiB
Plaintext
49 lines
1.2 KiB
Plaintext
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) get "input.ivy"
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alpha = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ"
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op vec str = or/ alpha o.== str
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# find the first occurence of an element in a vector
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op c index str = +/ and\ c != str
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# reshapes a vector as a 1-row matrix
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op lift v = (1, rho v) rho v
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op a concat b =
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0 == rho rho a: b
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0 == rho rho b: a
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a, b
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nl = "\n"
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null = 0 rho 0
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op m parse input =
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(rho input) == 0: m # if input is empty return the matrix
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i = nl index input # find the first newline
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k = (i+1) min (rho input)
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line = i take input # get chars before the newline
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rest = k drop input # get chars after the newline
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n = (rho line) / 2 # split line into two equal pieces
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A = vec n take line # and convert them to 1-hot vectors
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B = vec n drop line
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C = (lift A), (lift B) # make a pair
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m = m concat lift C # add the pair to the accumulator matrix
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m parse rest # recurse
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op parse input = null parse input
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op score m = +/ (iota rho alpha) * +/ transp m
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op solve m =
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score m[;1] and m[;2]
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op solve2 m =
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m = m[;1] or m[;2]
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n = (rho m)[1] / 3
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i = -2 + 3 * iota n
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score m[i] and m[i+1] and m[i+2]
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m = parse input
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solve m
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solve2 m
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