adventofcode2022/day19/sol.py

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import math
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import re
sample = {
1:{
'ore': [4, 0, 0, 0],
'clay': [2, 0, 0, 0],
'obsidian': [3, 14, 0, 0],
'geode': [2, 0, 7, 0],
},
2:{
'ore': [2, 0, 0, 0],
'clay': [3, 0, 0, 0],
'obsidian': [3, 8, 0, 0],
'geode': [3, 0, 12, 0],
}}
robot_number = {'ore': 0, 'clay': 1, 'obsidian': 2, 'geode': 3, 'nothing': 99}
def parse(line):
line = re.sub(r'[^\d]+', ' ', line)
idx, ore1, ore2, ore3, clay3, ore4, obs4 = map(int, line.split())
return idx, {
'ore': [ore1, 0,0,0],
'clay': [ore2, 0,0,0],
'obsidian': [ore3,clay3,0,0],
'geode': [ore4,0,obs4,0],
}
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def simulate(blueprint, minutes=24):
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B = blueprint
resources = [0]*4
robots = [1,0,0,0]
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rmax = [max(x[i] for x in B.values()) for i in range(3)] + [99]
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worth = {}
worth['ore'] = 1
worth['clay'] = worth['ore']*B['clay'][0]
worth['obsidian'] = worth['ore']*B['obsidian'][0] + worth['clay']*B['obsidian'][1]
worth['geode'] = worth['ore']*B['geode'][0] + worth['obsidian']*B['geode'][2]
print(worth)
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B_items = list(B.items())
B_items.reverse()
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#B_items.append(('nothing', [0,0,0,0]))
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print(B_items)
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buckets = [[] for _ in range(minutes+1)]
def enqueue(t, robots, resources):
if t < 0 or t >= len(buckets):
return
#x = (resources[3], max(resources[3], robots[3]), max(resources[2], robots[2]), max(resources[1], robots[1]), max(resources[0], robots[0]))
x = resources[3]
#w = sum(worth[r]*robots[robot_number[r]] for r in worth)
#x = tuple(reversed(resources+robots+[resources[3]]))
#x = (resources[3], robots)
#n = sum(x==0 for x in robots)
#if n == 3:
# x = (resources[0], robots[0])
#elif n == 2:
# x = (resources[1], resources[0], robots[1], robots[0])
#elif n == 1:
# x = (robots[3], min(resources[2],resources[0]), max(resources[2],resources[1]), robots[2], robots[1],robots[0])
#else:
# x = (resources[3], min(resources[2],resources[0]), max(resources[2],resources[0]), resources[1])
buckets[t].append((x,robots, resources))
enqueue(minutes, robots, resources)
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del resources
del robots
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max_geodes = 0
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for _ in range(minutes):
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#next = [[] for _ in range(4)]
buckets[minutes].sort(reverse=True)
print(minutes, buckets[minutes][:1])
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for _, robots, resources in buckets[minutes][:100000]:
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can_build = 0
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if robots[3]:
geodes = robots[3]*minutes + resources[3]
if geodes > max_geodes:
max_geodes = geodes
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for robot, cost in B_items:
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i = robot_number[robot]
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if robots[i] >= rmax[i]:
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# don't build more of 1 robot than we can spend in 1 minute
continue
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# figure out how soon we can afford it
wait = 0
for x,y,r in zip(resources, cost, robots):
if y == 0:
continue
if r <= 0:
wait = 9999
break
if y > x:
wait = max(wait, int(math.ceil((y - x)/r)))
if wait > minutes:
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continue
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new_resources = [x+(wait+1)*r-y for x,y,r in zip(resources, cost, robots)]
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if robot != 'nothing':
new_robots = list(robots)
new_robots[i] += 1
else:
new_robots = robots
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enqueue(minutes-wait-1, new_robots, new_resources)
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#print(len(next))
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#limit = 2500
#q = []
#for bucket in next:
# bucket.sort(reverse=True)
# q.extend(bucket[:limit])
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#count = sum(len(b) for b in next)
#print(count, q[:1])
print(minutes, [len(x) for x in buckets])
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buckets[minutes] = []
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minutes -= 1
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#print(buckets)
#q = buckets[0]
#print(q[0])
#return q[0][-1][-1]
return max_geodes
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#simulate(blueprints[1])
input = {}
with open('input') as f:
for line in f:
idx, bp = parse(line)
input[idx] = bp
def solve(input):
t = 0
for idx, B in input.items():
g = simulate(B)
t += idx*g
print(idx, g)
print("---")
print(t)
return t
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def solve2(input):
t = 1
for idx, B in input.items():
if idx <= 3:
g = simulate(B, minutes=32)
t *= g
print(t)
return t
#assert solve(sample) == 33
solve2(input)
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