day 22 part 1

main
magical 2023-12-22 06:23:52 +00:00
parent 52a2184a3c
commit f805d9d373
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day22/input 100644

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day22/sample1.in 100644
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1,0,1~1,2,1
0,0,2~2,0,2
0,2,3~2,2,3
0,0,4~0,2,4
2,0,5~2,2,5
0,1,6~2,1,6
1,1,8~1,1,9

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day22/sol.py 100644
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def overlaps(brick1, brick2):
"""reports whether two bricks overlap with each other"""
# the bricks as a whole overlap if there is any overlap
# on all three axes
for (a,b),(x,y) in zip(brick1, brick2):
if (b < x or a > y):
# ranges don't overlap
return False
return True
assert overlaps([(0,0), (1,2), (2,2)], [(0,0),(1,1),(2,3)])
assert not overlaps([(0,0), (1,1), (2,2)], [(1,1),(1,1),(2,2)])
def read_input(f):
data = []
for line in f:
start, end = line.split("~")
start = [int(x) for x in start.split(',')]
end = [int(x) for x in end .split(',')]
brick = [tuple(sorted([a,b])) for a,b in zip(start,end)]
data.append(brick)
return data
def check(data):
print(data)
for x in data:
for y in data:
if x == y:
assert overlaps(x,y)
else:
assert not overlaps(x,y)
print("ok")
def solve(f):
data = read_input(f)
check(data)
settle(data)
check(data)
disintegrate(data)
def settle(data):
def zindex(b):
return b[2]
data.sort(key=zindex)
top = 1
for i in range(len(data)):
# first, lower all blocks >i so that at least one block is at z=top
minz = min(z[0] for x,y,z in data[i:])
if minz > top:
print("lowering all blocks by", minz-top)
for b in data[i:]:
b[:] = lower(b, minz-top)
# lower blocks one at a time
b = data[i]
n = 0
while canlower(b, data[:i]):
b = lower(b)
n += 1
print("lowering block %d by %d" % (i,n))
data[i] = b
top = max(z[1] for x,y,z in data[:i+1]) + 1
def canlower(block, under):
if block[2][0] <= 1:
return False
x = lower(block)
for u in under:
if overlaps(u, x):
return False
return True
def disintegrate(data):
print(*data, sep="\n")
t = 0
#for i,x in enumerate(data):
# assert not canlower(x,data[:i])
for i,x in enumerate(data):
# disintegrate x
# find other blocks on the same z
#others = [y for y in data if x != y and not (y[2][1] < x[2][0] or y[2][0] > x[2][1])]
# see if any block can be lowered
# if yes, then x cannot be disintegrated
candisintegrate = True
for j in range(i+1, len(data)):
if canlower(data[j], data[:i] + data[i+1:j]):
candisintegrate = False
break
#ly = lower(y)
#if y == ly:
# continue
#supports = [z for z in others if z != x and z != y and overlaps(z,ly)]
#if supports:
# # theer is a block that supports y
# #candisintegrate = True
# print('y = %s would be blocked by %d blocks' % (y, len(supports)))
# pass
#else:
# # no block would stop y from falling
# print("no blockk stops y=%s" % (y))
# candisintegrate = False
# break
print(i, x, candisintegrate)
if candisintegrate:
t += 1
print(t)
return (t)
def lower(brick, n=1):
"""lower a brick n spaces in the z direction"""
x, y, z = brick
if z[0] > 1:
z = z[0]-1, z[1]-1
return [x, y, z]
import sys
solve(sys.stdin)