def parse(file):
    while True:
        a = file.readline()
        if not a:
            break
        b = file.readline()
        pr = file.readline()
        blank = file.readline()

        ax, ay = parse_numbers(a)
        bx, by = parse_numbers(b)
        px, py = parse_numbers(pr)
        yield ax,ay, bx,by, px,py

import re
def parse_numbers(s):
    return [int(x) for x in re.findall(r"\d+", s)]

from fractions import Fraction as F

import numpy
def solve(file):
    total = 0
    total2 = 0
    records = list(parse(file))
    for record in records:
        #print(record)
        ax, ay, bx, by, px, py = record

        # Part 1

        # Solve the linear equation:
        # k_a ax + k_b * bx = px
        # k_a ay + k_b * by = py
        
        M = numpy.array([[ax, bx], [ay, by]])
        V = numpy.array([px, py])
        sol = numpy.linalg.solve(M,V)
        k1 = int(round(sol[0]))
        k2 = int(round(sol[1]))
        if k1*ax + k2*bx == px and k1*ay + k2*by == py:
            print("yes", k1, k2)
            total += 3*k1 + k2

    for record in records:
        ax, ay, bx, by, px, py = record

        # Part 2
        #
        # Can't use numpy because the values are too large for floats
        # So here's an ad-hoc solver

        px += 10000000000000
        py += 10000000000000

        m00, m01 = ax, bx
        m10, m11 = ay, by
        v1 = px
        v2 = py
        
        # subtract c*eq1 from eq2 to cancel first coefficient
        c = F(m10,m00)
        m10 -= c*m00
        m11 -= c*m01
        v2  -= c*v1

        # scale eq2
        c = F(1,m11)
        v2 *= c
        m11 *= c

        # subtract c*eq2 from eq1 to cancel second coefficient
        c = F(m01,m11)
        m01 -= c*m11
        v1  -= c*v2

        # scale eq1
        c = F(1,m00)
        v1  *= c
        m00 *= c

        # we now have
        # 1*k_a + 0     = v1
        # 0     + 1*k_b = v2

        print(m00, m01, m10, m11, v1, v2)
        if v1.denominator == 1 and v2.denominator == 1 and v1 > 0 and v2 > 0:
            if v1*ax + v2*bx == px and v1*ay + v2*by == py:
                print("yes2", v1, v2)
                total2 += 3*v1 + v2

        
    print(total)
    print(total2)


solve(open("sample1.in"))
solve(open("input"))